Integrand size = 28, antiderivative size = 47 \[ \int \frac {\sqrt {2-3 x}}{\sqrt {-5+2 x} \sqrt {1+4 x}} \, dx=\frac {\sqrt {\frac {11}{2}} \sqrt {5-2 x} E\left (\left .\arcsin \left (\frac {\sqrt {1+4 x}}{\sqrt {11}}\right )\right |3\right )}{2 \sqrt {-5+2 x}} \]
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Time = 0.01 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {115, 114} \[ \int \frac {\sqrt {2-3 x}}{\sqrt {-5+2 x} \sqrt {1+4 x}} \, dx=\frac {\sqrt {\frac {11}{2}} \sqrt {5-2 x} E\left (\left .\arcsin \left (\frac {\sqrt {4 x+1}}{\sqrt {11}}\right )\right |3\right )}{2 \sqrt {2 x-5}} \]
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Rule 114
Rule 115
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {5-2 x} \int \frac {\sqrt {\frac {8}{11}-\frac {12 x}{11}}}{\sqrt {\frac {10}{11}-\frac {4 x}{11}} \sqrt {1+4 x}} \, dx}{\sqrt {2} \sqrt {-5+2 x}} \\ & = \frac {\sqrt {\frac {11}{2}} \sqrt {5-2 x} E\left (\left .\sin ^{-1}\left (\frac {\sqrt {1+4 x}}{\sqrt {11}}\right )\right |3\right )}{2 \sqrt {-5+2 x}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(111\) vs. \(2(47)=94\).
Time = 2.33 (sec) , antiderivative size = 111, normalized size of antiderivative = 2.36 \[ \int \frac {\sqrt {2-3 x}}{\sqrt {-5+2 x} \sqrt {1+4 x}} \, dx=-\frac {\frac {2 (-5+2 x) (-2+3 x)}{\sqrt {\frac {1}{2}+2 x}}+\sqrt {11} \sqrt {\frac {-5+2 x}{1+4 x}} \sqrt {\frac {-2+3 x}{1+4 x}} (1+4 x) E\left (\left .\arcsin \left (\frac {\sqrt {\frac {11}{3}}}{\sqrt {1+4 x}}\right )\right |3\right )}{2 \sqrt {2-3 x} \sqrt {-10+4 x}} \]
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Time = 1.58 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.70
method | result | size |
default | \(\frac {E\left (\frac {\sqrt {11+44 x}}{11}, \sqrt {3}\right ) \sqrt {5-2 x}\, \sqrt {22}}{4 \sqrt {-5+2 x}}\) | \(33\) |
elliptic | \(\frac {\sqrt {-\left (-2+3 x \right ) \left (-5+2 x \right ) \left (1+4 x \right )}\, \left (\frac {2 \sqrt {11+44 x}\, \sqrt {22-33 x}\, \sqrt {110-44 x}\, F\left (\frac {\sqrt {11+44 x}}{11}, \sqrt {3}\right )}{121 \sqrt {-24 x^{3}+70 x^{2}-21 x -10}}-\frac {3 \sqrt {11+44 x}\, \sqrt {22-33 x}\, \sqrt {110-44 x}\, \left (-\frac {11 E\left (\frac {\sqrt {11+44 x}}{11}, \sqrt {3}\right )}{12}+\frac {2 F\left (\frac {\sqrt {11+44 x}}{11}, \sqrt {3}\right )}{3}\right )}{121 \sqrt {-24 x^{3}+70 x^{2}-21 x -10}}\right )}{\sqrt {2-3 x}\, \sqrt {-5+2 x}\, \sqrt {1+4 x}}\) | \(167\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.07 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.55 \[ \int \frac {\sqrt {2-3 x}}{\sqrt {-5+2 x} \sqrt {1+4 x}} \, dx=\frac {11}{72} \, \sqrt {-6} {\rm weierstrassPInverse}\left (\frac {847}{108}, \frac {6655}{2916}, x - \frac {35}{36}\right ) - \frac {1}{2} \, \sqrt {-6} {\rm weierstrassZeta}\left (\frac {847}{108}, \frac {6655}{2916}, {\rm weierstrassPInverse}\left (\frac {847}{108}, \frac {6655}{2916}, x - \frac {35}{36}\right )\right ) \]
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\[ \int \frac {\sqrt {2-3 x}}{\sqrt {-5+2 x} \sqrt {1+4 x}} \, dx=\int \frac {\sqrt {2 - 3 x}}{\sqrt {2 x - 5} \sqrt {4 x + 1}}\, dx \]
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\[ \int \frac {\sqrt {2-3 x}}{\sqrt {-5+2 x} \sqrt {1+4 x}} \, dx=\int { \frac {\sqrt {-3 \, x + 2}}{\sqrt {4 \, x + 1} \sqrt {2 \, x - 5}} \,d x } \]
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\[ \int \frac {\sqrt {2-3 x}}{\sqrt {-5+2 x} \sqrt {1+4 x}} \, dx=\int { \frac {\sqrt {-3 \, x + 2}}{\sqrt {4 \, x + 1} \sqrt {2 \, x - 5}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {2-3 x}}{\sqrt {-5+2 x} \sqrt {1+4 x}} \, dx=\int \frac {\sqrt {2-3\,x}}{\sqrt {4\,x+1}\,\sqrt {2\,x-5}} \,d x \]
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